Do the following pair of linear equations have no solution? Justify your answer.
$y + 6x = 6$ and $y = 2x$

(B) The condition for a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have no solution is $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$.
Given equations are:
$6x + y - 6 = 0$ --- $(i)$
$2x - y = 0$ --- $(ii)$
Here,$a_1 = 6, b_1 = 1, c_1 = -6$ and $a_2 = 2, b_2 = -1, c_2 = 0$.
Calculating the ratios:
$\frac{a_1}{a_2} = \frac{6}{2} = 3$
$\frac{b_1}{b_2} = \frac{1}{-1} = -1$
Since $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$ $(3 \neq -1)$,the lines intersect at a single point.
Therefore,the given pair of linear equations has a unique solution,not 'no solution'.