Domain of the function log |x^2 - 9| is | vedclass

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(C) The function $f(x) = \log |x^2 - 9|$ is defined only when the argument of the logarithm is strictly positive.That is,$|x^2 - 9| > 0$.Since the abs

Vedclass · Accepted Answer

$R - \{-3, 3\}$

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(C) The function $f(x) = \log |x^2 - 9|$ is defined only when the argument of the logarithm is strictly positive.That is,$|x^2 - 9| > 0$.Since the absolute value $|x^2 - 9|$ is always non-negative,the condition $|x^2 - 9| > 0$ is satisfied for all real numbers $x$ except where $|x^2 - 9| = 0$.Setting $x^2 - 9 = 0$,we get $x^2 = 9$,which implies $x = 3$ or $x = -3$.Therefore,the function is undefined at $x = 3$ and $x = -3$.Thus,the domain of the function is all real numbers except $\{-3, 3\}$,which is written as $R - \{-3, 3\}$.

Domain of the function $\log |x^2 - 9|$ is

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