Draw a line segment $\overline{PQ}$ of length $8.2 \, cm$ and divide it in the ratio $3:7$ from point $P$. Write the steps of construction.

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(N/A) Steps of construction:
$1$. Draw a line segment $\overline{PQ} = 8.2 \, cm$ using a ruler.
$2$. Draw an acute angle $\angle QPX$ at point $P$ below the line segment $\overline{PQ}$.
$3$. Starting from $P$,mark $3 + 7 = 10$ points $A_1, A_2, A_3, \dots, A_{10}$ on the ray $PX$ such that $PA_1 = A_1A_2 = A_2A_3 = \dots = A_9A_{10}$.
$4$. Join the point $A_{10}$ to $Q$.
$5$. Through point $A_3$,draw a line parallel to $A_{10}Q$ intersecting $\overline{PQ}$ at point $R$.
$6$. The point $R$ divides $\overline{PQ}$ in the ratio $3:7$ such that $PR:RQ = 3:7$.

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Write True or False and give reasons for your answer.
By geometrical construction,it is possible to divide a line segment in the ratio $\sqrt{3}: \frac{1}{\sqrt{3}}$.

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