Draw $\overline{PQ}$ of length $8.5 \text{ cm}$ and obtain point $X$ on $\overline{PQ}$ such that $PX : XQ = 4 : 7$. Write the steps of construction.

(N/A) Steps of construction:
$1$. Draw a line segment $\overline{PQ}$ of length $8.5 \text{ cm}$ using a ruler.
$2$. Draw any ray $PY$ making an acute angle with $\overline{PQ}$.
$3$. Locate $4 + 7 = 11$ points $A_1, A_2, \dots, A_{11}$ on ray $PY$ such that $PA_1 = A_1A_2 = A_2A_3 = \dots = A_{10}A_{11}$.
$4$. Join $A_{11}$ to $Q$.
$5$. Through the point $A_4$ (since the ratio is $4:7$),draw a line parallel to $A_{11}Q$ intersecting $\overline{PQ}$ at point $X$.
$6$. Thus,$X$ is the point on $\overline{PQ}$ which divides it in the ratio $4 : 7$.