Due to 10 A of current flowing in a circular | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field $B$ at the centre of a circular coil with $N$ turns is given by the formula: $B = \frac{\mu_0 N I}{2r}$.Given values are: Curre

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(C) The magnetic field $B$ at the centre of a circular coil with $N$ turns is given by the formula: $B = \frac{\mu_0 N I}{2r}$.Given values are: Current $I = 10 \ A$,Radius $r = 10 \ cm = 0.1 \ m$,Magnetic field $B = 3.14 	imes 10^{-3} \ Wb/m^2$,and $\mu_0 = 4\pi 	imes 10^{-7} \ T \cdot m/A$.Substituting the values into the formula:$3.14 	imes 10^{-3} = \frac{(4\pi 	imes 10^{-7}) 	imes N 	imes 10}{2 	imes 0.1}$.Using $\pi \approx 3.14$,we get:$3.14 	imes 10^{-3} = \frac{4 	imes 3.14 	imes 10^{-7} 	imes N 	imes 10}{0.2}$.$3.14 	imes 10^{-3} = 20 	imes 3.14 	imes 10^{-6} 	imes N$.$10^{-3} = 20 	imes 10^{-6} 	imes N$.$N = \frac{10^{-3}}{20 	imes 10^{-6}} = \frac{1000}{20} = 50$.Therefore,the number of turns in the coil is $50$.

Due to $10 \ A$ of current flowing in a circular coil of $10 \ cm$ radius,the magnetic field produced at its centre is $3.14 \times 10^{-3} \ Wb/m^2$. The number of turns in the coil will be:

Similar Questions

Which of the following figures correctly depicts the direction of the magnetic field of a current-carrying coil?

$A$ steady current flows in a long wire. It is bent into a circular loop of one turn and the magnetic field at the centre of the coil is $B$. If the same wire is bent into a circular loop of $n$ turns, the magnetic field at the centre of the coil is

$A$ current of $1.5 \, A$ is flowing through an equilateral triangle of side $9 \, cm$. The magnetic field at the centroid of the triangle is (Assume that the current is flowing in the clockwise direction.)

$A$ current-carrying wire in its neighbourhood produces:

The source of magnetic field is . . . . . . and source of electric field is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module