During an adiabatic process, the pressure of | vedclass

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(A) For an adiabatic process, the relationship between pressure $P$ and absolute temperature $T$ is given by $P^{1-\gamma} T^{\gamma} = 	ext{constant

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(A) For an adiabatic process, the relationship between pressure $P$ and absolute temperature $T$ is given by $P^{1-\gamma} T^{\gamma} = 	ext{constant}$, which can be rewritten as $P \propto T^{\frac{\gamma}{\gamma-1}}$.Given that $P \propto T^3$, we compare the exponents:$\frac{\gamma}{\gamma-1} = 3$$\gamma = 3(\gamma - 1)$$\gamma = 3\gamma - 3$$2\gamma = 3$$\gamma = \frac{3}{2} = 1.5$.Since the ratio ${C_p}/{C_v}$ is equal to the adiabatic index $\gamma$, the value is $1.5$.

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio ${C_p}/{C_v}$ for the gas is

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