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(C) In the carboxylation phase of the Calvin cycle,Ribulose-$1,5$-bisphosphate $(RuBP)$,which is a $5$-carbon compound,acts as the primary $CO_2$ acce

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$RuBP + CO_2$

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(C) In the carboxylation phase of the Calvin cycle,Ribulose-$1,5$-bisphosphate $(RuBP)$,which is a $5$-carbon compound,acts as the primary $CO_2$ acceptor.Each molecule of $RuBP$ reacts with one molecule of $CO_2$ in the presence of the enzyme $RuBisCO$ to form an unstable $6$-carbon intermediate.This intermediate immediately splits into two molecules of $3$-phosphoglyceric acid $(PGA)$,which is a $3$-carbon compound.Therefore,the carbon atoms in $PGA$ are derived from both the $5$-carbon $RuBP$ and the $1$-carbon $CO_2$ molecule.

During the dark reaction for the fixation of carbon,the three carbon atoms of each molecule of $3$-phosphoglyceric acid $(PGA)$ are derived from

Similar Questions

The first stable intermediate product formed during the Calvin cycle of photosynthesis is:

Who received the Nobel Prize for working out the early carbon pathway of photosynthesis?

In $C_3$ plants, what are the primary $CO_2$ acceptor and the carboxylating enzyme, respectively?

$A-$ RuBisCO,which is the most abundant enzyme in the world,is characterized by the fact that its active site can bind to both $CO_2$ and $O_2$.
$R-$ RuBisCO is the most abundant enzyme in the world.

Why is regeneration necessary in the Calvin cycle?

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