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Question

(B) For an electromagnetic wave,the relationship between the amplitudes of the electric field $(E_0)$ and magnetic field $(B_0)$ is given by $E_0 = cB

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Electric energy density is equal to the magnetic energy density

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(B) For an electromagnetic wave,the relationship between the amplitudes of the electric field $(E_0)$ and magnetic field $(B_0)$ is given by $E_0 = cB_0$,where $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$.The electric energy density is given by $u_E = \frac{1}{2} \varepsilon_0 E_0^2$.The magnetic energy density is given by $u_B = \frac{1}{2} \frac{B_0^2}{\mu_0}$.Substituting $E_0 = cB_0$ into the electric energy density formula:$u_E = \frac{1}{2} \varepsilon_0 (cB_0)^2 = \frac{1}{2} \varepsilon_0 \left(\frac{1}{\mu_0 \varepsilon_0}\right) B_0^2 = \frac{1}{2} \frac{B_0^2}{\mu_0}$.Therefore,$u_E = u_B$. The energy is equally divided between the electric and magnetic fields.

During the propagation of electromagnetic waves in a medium,

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