The energy of all molecules of a monoatomic g | vedclass

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(B) The number of translational degrees of freedom for any gas molecule (monoatomic,diatomic,or polyatomic) is always $3$.The translational kinetic en

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$\frac{3}{2}PV$

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(B) The number of translational degrees of freedom for any gas molecule (monoatomic,diatomic,or polyatomic) is always $3$.The translational kinetic energy $(KE_{trans})$ of a gas is given by the formula $KE_{trans} = \frac{3}{2}nRT$.From the ideal gas equation,we know that $PV = nRT$.Substituting this into the kinetic energy formula,we get $KE_{trans} = \frac{3}{2}PV$.Since the volume $V$ and pressure $P$ are the same for both the monoatomic and diatomic gases,the total translational kinetic energy remains $\frac{3}{2}PV$ for the diatomic gas as well.

The energy of all molecules of a monoatomic gas having a volume $V$ and pressure $P$ is $\frac{3}{2}PV$. The total translational kinetic energy of all molecules of a diatomic gas at the same volume and pressure is:

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