The equation of a line is $3x - 4y + 10 = 0$. Find its slope.

The straight line $L$ is perpendicular to the line $5x - y = 1$. If the area of the triangle formed by the line $L$ and the coordinate axes is $5$,find the equation of the line $L$.

Find the equation of the line passing through the intersection of the lines $y = 3$ and $x + y = 0$ and parallel to the line $2x - y = 4$.

If $(a, -2a), a > 0$ is the midpoint of a line segment intercepted between the coordinate axes,then the equation of the line is

$A$ line $L$ passes through the point $P(1, 2)$ and makes an angle of $60^{\circ}$ with the positive $X$-axis. $A$ and $B$ are two points lying on $L$ at a distance of $4$ units from $P$. If $O$ is the origin,then the area of $\triangle OAB$ is

The equation of the line parallel to the line $3x - 4y + 2 = 0$ and passing through $(-2, 3)$ is