If $(a, -2a), a > 0$ is the midpoint of a line segment intercepted between the coordinate axes,then the equation of the line is

Find the value of $x$ for which the points $(x, -1), (2, 1),$ and $(4, 5)$ are collinear.

The equation of a line passing through the origin and perpendicular to the line joining $(a, 0)$ and $(-a, 0)$ is

Match the items given in List-$I$ to the items given in List-$II$.

List-$I$	List-$II$
$A$. Line passing through $(-4, 3)$ and having intercepts in the ratio $5:3$	$1$. $2x - 5y + 4 = 0$
$B$. Line passing through $P(2, -5)$ such that $P$ bisects the part intercepted between the axes	$2$. $3x + 5y = 3$
$C$. Line parallel to $2x - 3y + 5 = 0$ with $x$-intercept $\frac{2}{5}$ is	$3$. $10x - 15y + 4 = 0$
$D$. Line perpendicular to $5x + 2y + 7 = 0$ with $y$-intercept $\frac{4}{5}$ is	$4$. $10x - 15y = 4$
	$5$. $5x - 2y - 20 = 0$

The owner of a milk store finds that he can sell $980$ liters of milk each week at Rs $14$ per liter and $1220$ liters of milk each week at Rs $16$ per liter. Assuming a linear relationship between selling price and demand,how many liters could he sell weekly at Rs $17$ per liter?

The equation of the line passing through the points $(1, 2)$ and $(2, 5)$ is: