The equations of the diagonals of the square | vedclass

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Question

(A) The vertices of the square are formed by the intersection of the given lines: $A(0, 0)$ (intersection of $x=0$ and $y=0$),$B(0, 1)$ (intersection

Vedclass · Accepted Answer

$y = x, \; y + x = 1$

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(A) The vertices of the square are formed by the intersection of the given lines: $A(0, 0)$ (intersection of $x=0$ and $y=0$),$B(0, 1)$ (intersection of $x=0$ and $y=1$),$C(1, 1)$ (intersection of $x=1$ and $y=1$),$D(1, 0)$ (intersection of $x=1$ and $y=0$). The diagonals are the lines joining opposite vertices $A(0, 0)$ to $C(1, 1)$ and $B(0, 1)$ to $D(1, 0)$. $1$. For diagonal $AC$: The slope $m = \frac{1-0}{1-0} = 1$. The equation is $y - 0 = 1(x - 0) \Rightarrow y = x$. $2$. For diagonal $BD$: The slope $m = \frac{0-1}{1-0} = -1$. The equation is $y - 1 = -1(x - 0)$ $\Rightarrow y - 1 = -x$ $\Rightarrow x + y = 1$.

The equations of the diagonals of the square formed by the lines $x = 0,$ $y = 0,$ $x = 1,$ and $y = 1$ are

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