Ethanol and phenol cannot be distinguished by

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(D) $1$. $I_2/NaOH$ (Iodoform test): Ethanol gives a positive iodoform test (yellow precipitate),whereas phenol does not. Thus,they can be distinguish

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$NaHCO_3$

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(D) $1$. $I_2/NaOH$ (Iodoform test): Ethanol gives a positive iodoform test (yellow precipitate),whereas phenol does not. Thus,they can be distinguished.$2$. Neutral $FeCl_3$: Phenol gives a violet color with neutral $FeCl_3$ solution,while ethanol does not. Thus,they can be distinguished.$3$. $Br_2/H_2O$: Phenol gives a white precipitate of $2,4,6-tribromophenol$ with bromine water,while ethanol does not react. Thus,they can be distinguished.$4$. $NaHCO_3$: Neither ethanol nor phenol is acidic enough to react with $NaHCO_3$ to evolve $CO_2$ gas. Therefore,they cannot be distinguished by this reagent.

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