Ethylene is converted to X on passing through | vedclass

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Question

(D) The reaction described is the Wacker process,where ethylene $(CH_2=CH_2)$ is oxidized to acetaldehyde $(CH_3CHO)$ in the presence of $PdCl_2$ and

Vedclass · Accepted Answer

$HCN$

Vedclass · Answer

(D) The reaction described is the Wacker process,where ethylene $(CH_2=CH_2)$ is oxidized to acetaldehyde $(CH_3CHO)$ in the presence of $PdCl_2$ and $CuCl_2$. Thus,$X$ is acetaldehyde $(CH_3CHO)$. Acetaldehyde contains a carbonyl group $(C=O)$ and undergoes nucleophilic addition reactions. Among the given options,$HCN$ (hydrogen cyanide) is a classic reagent that readily undergoes nucleophilic addition with the carbonyl group of aldehydes to form cyanohydrins. Therefore,$HCN$ is the correct reagent.

Ethylene is converted to $X$ on passing through a mixture of an acidified aqueous solution of palladium chloride and cupric chloride. Which of the following reagents readily take part in addition reaction with $X$?

Similar Questions

The product $(B)$ is:

Correct order for nucleophilic addition reaction :
$(1)$ $C_{6}H_{5}COC_{6}H_{5}$
$(2)$ $C_{6}H_{5}CHO$
$(3)$ $p-CH_{3}C_{6}H_{4}CHO$
$(4)$ $p-CH_{3}OC_{6}H_{4}CHO$

In the reaction sequence,
$Cyclohex-2-en-1-one \xrightarrow[(ii) H_2O/H^+]{(i) CH_3MgBr/CuCl} (X)$
Product $(X)$ will be:

To distinguish between formaldehyde and acetaldehyde,we require

In the reaction of benzaldehyde with acetaldehyde in the presence of dilute $NaOH$,the product $(A)$ will be:

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