To distinguish between formaldehyde and aceta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Formaldehyde $(HCHO)$ and acetaldehyde $(CH_3CHO)$ can be distinguished using caustic soda $(NaOH)$ solution.Formaldehyde undergoes the Cannizzaro

Vedclass · Accepted Answer

Caustic soda solution

Vedclass · Answer

(D) Formaldehyde $(HCHO)$ and acetaldehyde $(CH_3CHO)$ can be distinguished using caustic soda $(NaOH)$ solution.Formaldehyde undergoes the Cannizzaro reaction because it lacks $\alpha$-hydrogen atoms:$2HCHO + NaOH (conc.) \rightarrow CH_3OH + HCOONa$Acetaldehyde undergoes aldol condensation because it possesses $\alpha$-hydrogen atoms:$2CH_3CHO \xrightarrow{NaOH (dil.)} CH_3-CH(OH)-CH_2-CHO$Thus,option $(D)$ is the correct choice.

To distinguish between formaldehyde and acetaldehyde,we require

Similar Questions

The key step in Cannizzaro's reaction is the intermolecular shift of

The products $(A)$ and $(B)$ respectively in the above reaction are:

Which of the following compounds does not give the iodoform test?

$2CD_2=O + OH^- \xrightarrow{\quad} X + Y$ ($Y$ is an alcohol and $D$ is deuterium). Identify $X$ and $Y$.

$CH_3CO_2Et + (CH_2)_5(MgBr)_2 \xrightarrow[(2) H^{+}]{(1)} \mathop {C_7H_{14}O}\limits_{(A)}$ ; compound $(A)$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module