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If $x$ takes a negative permissible value,then $\sin^{-1} x$ is equal to
DifficultKCET 2009
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Prove that $\tan ^{-1} x+\tan ^{-1} \frac{2 x}{1-x^{2}}=\tan ^{-1}\left(\frac{3 x-x^{3}}{1-3 x^{2}}\right)$,where $|x| < \frac{1}{\sqrt{3}}$.
Medium
View Solution$\sin^{-1} \frac{1}{\sqrt{5}} + \cot^{-1} 3$ is equal to
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View Solution$\cos \left[ {{\tan }^{ - 1}}\frac{1}{3} + {{\tan }^{ - 1}}\frac{1}{2} \right] = $
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