Evaluate:cos 48^{circ}-sin 42^{circ} | vedclass

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(A) We know the trigonometric identity: $\cos(90^{\circ}-	heta) = \sin 	heta$.Given expression: $\cos 48^{\circ}-\sin 42^{\circ}$.We can write $\cos

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(A) We know the trigonometric identity: $\cos(90^{\circ}-	heta) = \sin 	heta$.Given expression: $\cos 48^{\circ}-\sin 42^{\circ}$.We can write $\cos 48^{\circ}$ as $\cos(90^{\circ}-42^{\circ})$.Using the identity,$\cos(90^{\circ}-42^{\circ}) = \sin 42^{\circ}$.Substituting this into the expression:$\sin 42^{\circ} - \sin 42^{\circ} = 0$.

Evaluate:
$\cos 48^{\circ}-\sin 42^{\circ}$

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Evaluate:$\cos 48^{\circ}-\sin 42^{\circ}$