$\sin \theta \cdot \cos (90^\circ - \theta) = \ldots \ldots \ldots$
- A$\tan \theta$
- B$\sin^2 \theta$
- C$\cos^2 \theta$
- D$\sin \theta \cdot \sec \theta$
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Similar Questions
Which of the following pairs is correct for trigonometric inter-relationships?
$1. \cos \theta$ $a. \frac{\cos \theta}{\sin \theta}$ $2. \tan \theta$ $b. \frac{1}{\csc \theta}$ $3. \cot \theta$ $c. \frac{1}{\sec \theta}$ $4. \sin \theta$ $d. \frac{1}{\cot \theta}$ $e. \sin \theta \cdot \cos \theta$
| $1. \cos \theta$ | $a. \frac{\cos \theta}{\sin \theta}$ |
| $2. \tan \theta$ | $b. \frac{1}{\csc \theta}$ |
| $3. \cot \theta$ | $c. \frac{1}{\sec \theta}$ |
| $4. \sin \theta$ | $d. \frac{1}{\cot \theta}$ |
| $e. \sin \theta \cdot \cos \theta$ |
Easy
View SolutionIf $\cot \theta = \frac{7}{8},$ evaluate:
$(i) \frac{(1+\sin \theta)(1-\sin \theta)}{(1+\cos \theta)(1-\cos \theta)}$
$(ii) \cot^2 \theta$
$(i) \frac{(1+\sin \theta)(1-\sin \theta)}{(1+\cos \theta)(1-\cos \theta)}$
$(ii) \cot^2 \theta$
Difficult
View SolutionIf $\cot \theta = \frac{a}{b}$,then $\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta} = \ldots$
Medium
View SolutionIn $\triangle PQR$, right-angled at $Q$, $PR + QR = 25 \, cm$ and $PQ = 5 \, cm$. Determine the values of $\sin P, \cos P$ and $\tan P$.
Medium
View SolutionIf $\sin A = \frac{3}{4},$ calculate $\cos A$ and $\tan A$.
Medium
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