If cot theta = frac{a}{b},then frac{cos theta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given $\cot 	heta = \frac{a}{b}$.We know that $\cot 	heta = \frac{\cos 	heta}{\sin 	heta}$,so $\frac{\cos 	heta}{\sin 	heta} = \frac{a}{b}$.

Vedclass · Accepted Answer

$\frac{a-b}{a+b}$

Vedclass · Answer

(D) Given $\cot 	heta = \frac{a}{b}$.We know that $\cot 	heta = \frac{\cos 	heta}{\sin 	heta}$,so $\frac{\cos 	heta}{\sin 	heta} = \frac{a}{b}$.To evaluate $\frac{\cos 	heta - \sin 	heta}{\cos 	heta + \sin 	heta}$,divide both the numerator and the denominator by $\sin 	heta$:$\frac{\frac{\cos 	heta}{\sin 	heta} - \frac{\sin 	heta}{\sin 	heta}}{\frac{\cos 	heta}{\sin 	heta} + \frac{\sin 	heta}{\sin 	heta}} = \frac{\cot 	heta - 1}{\cot 	heta + 1}$.Substituting $\cot 	heta = \frac{a}{b}$:$\frac{\frac{a}{b} - 1}{\frac{a}{b} + 1} = \frac{\frac{a-b}{b}}{\frac{a+b}{b}} = \frac{a-b}{a+b}$.

If $\cot \theta = \frac{a}{b}$,then $\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta} = \ldots$

Similar Questions

$5 \cos A = 4 \sin A$,then $\tan A = \ldots$

$\sin 48^{\circ} \sec 42^{\circ} + \cos 48^{\circ} \operatorname{cosec} 42^{\circ} = \ldots \ldots \ldots \ldots$

If $\cos 9 \alpha = \sin \alpha$ and $9 \alpha < 90^{\circ},$ then the value of $\tan 5 \alpha$ is

Which of the following is true for some $\theta$ (where,$0 < \theta < 90^{\circ}$)?

In $\Delta ABC$,$m \angle B = 90^{\circ}$. If $m \angle C = \theta$,then $\tan \theta = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module