In $\Delta ABC$,$m \angle B = 90^{\circ}$. If $m \angle C = \theta$,then $\tan \theta = \dots$
- A$\frac{AB}{AC}$
- B$\frac{AC}{AB}$
- C$\frac{BC}{AB}$
- D$\frac{AB}{BC}$
Explore More
Similar Questions
If $\operatorname{cosec} A = \sqrt{10}$,then $\sin A = \dots$
Easy
View SolutionIf $\angle B$ and $\angle Q$ are acute angles such that $\sin B = \sin Q$,then prove that $\angle B = \angle Q$.
Easy
View SolutionWrite 'True' or 'False' and justify your answer.
$\tan \theta$ increases faster than $\sin \theta$ as $\theta$ increases for $0^\circ < \theta < 90^\circ$.
$\tan \theta$ increases faster than $\sin \theta$ as $\theta$ increases for $0^\circ < \theta < 90^\circ$.
Easy
View SolutionWhich of the following is true for some $\theta$ (where,$0 < \theta < 90^{\circ}$)?
Easy
View Solution$\sin \theta \cdot \cos (90^\circ - \theta) = \ldots \ldots \ldots$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo