Expand left(frac{2x}{3} + frac{4y}{5}right) l | vedclass

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(B) The given expression is in the form of $(a + b)(a - b)$,where $a = \frac{2x}{3}$ and $b = \frac{4y}{5}$.Using the algebraic identity $(a + b)(a -

Vedclass · Accepted Answer

$\frac{4}{9}x^2 - \frac{16}{25}y^2$

Vedclass · Answer

(B) The given expression is in the form of $(a + b)(a - b)$,where $a = \frac{2x}{3}$ and $b = \frac{4y}{5}$.Using the algebraic identity $(a + b)(a - b) = a^2 - b^2$,we get:$\left(\frac{2x}{3}\right)^2 - \left(\frac{4y}{5}\right)^2$$= \frac{4x^2}{9} - \frac{16y^2}{25}$$= \frac{4}{9}x^2 - \frac{16}{25}y^2$.

Expand $\left(\frac{2x}{3} + \frac{4y}{5}\right) \left(\frac{2x}{3} - \frac{4y}{5}\right)$.

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