Explain why $((CH_3)_3C)^+$ is more stable than $(CH_3CH_2)^+$ and $(CH_3)^+$ is the least stable carbocation.

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(N/A) The stability of carbocations is primarily determined by the inductive effect and hyperconjugation.
In $((CH_3)_3C)^+$,there are $9$ $\alpha$-$C-H$ bonds available for hyperconjugation,which provides significant stabilization.
In $(CH_3CH_2)^+$,there are only $3$ $\alpha$-$C-H$ bonds available for hyperconjugation,making it less stable than the tertiary carbocation.
In $(CH_3)^+$,there are no $\alpha$-$C-H$ bonds available for hyperconjugation. Furthermore,the vacant $p$-orbital is perpendicular to the plane of the $C-H$ bonds,preventing any overlap. Thus,$(CH_3)^+$ lacks hyperconjugative stability and is the least stable.

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Similar Questions

Arrange the following carbocations in the increasing order of stability with respect to their labels:
LabelCarbocation
$1$$CH_3-CH^+-CH_3$
$2$$CH_3^+$
$3$$(CH_3)_3C^+$
$4$$CH_3-CH_2^+$

With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

Which of the following is the least stable carbon free radical?

Arrange the following carbanions in the decreasing order of their stability:
$(1) CH_3-CH_2^-, (2) CH_2=CH^-, (3) HC \equiv C^-$

Which of the following is the most stable carbocation?

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