Explain with illustrations the meaning of work,energy,and power in everyday life and state that this meaning has no relation with the meaning in physics.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In everyday life,activities like a farmer tilling a field,a laborer carrying bricks,a student studying for exams,or an artist painting a picture are considered 'work'. However,in physics,work is defined as $W = \vec{F} \cdot \vec{d} = Fd \cos \theta$. If there is no displacement,the work done is zero,regardless of the effort exerted.
Similarly,when we say a person has high 'energy' because they work $14$ to $16$ hours a day,we refer to their stamina or endurance. In physics,energy is defined as the capacity to do work,which is a quantitative scalar property.
Finally,the term 'power' in daily life often refers to influence,authority,or social status (e.g.,'showing your power'). In physics,power is defined as the rate at which work is done or energy is transferred,given by $P = \frac{dW}{dt}$.

Explore More

Similar Questions

$A$ ball is allowed to fall from a height of $10 \, m$. If there is $40 \%$ loss of energy due to impact,then after one impact the ball will rise to a height of ........ $m$.

$A$ body of mass $5 \,kg$ falls from a height of $30 \,m$. If all its mechanical energy is converted into heat,then the heat produced will be ........ $cal$.

$A$ force exerts an impulse $I$ on a particle changing its speed from $u$ to $2u$. The applied force and the initial velocity are oppositely directed along the same line. The work done by the force is

Difficult
View Solution

Assertion $(A)$: In an elastic collision of two billiard balls,the total kinetic energy $(KE)$ is conserved during the short time of collision of the balls (i.e.,when they are in contact).
Reason $(R)$: Energy spent against friction does not follow the law of conservation of energy.

$A$ sphere of mass $m$ travelling at constant speed $v$ strikes another sphere of the same mass. If the coefficient of restitution is $e$,then the ratio of the velocities of both spheres just after the collision is:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo