Factorise: a^{3} - 2sqrt{2}b^{3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We use the algebraic identity: $a^{3} - b^{3} = (a - b)(a^{2} + ab + b^{2})$.Given expression: $a^{3} - 2\sqrt{2}b^{3}$.Rewrite the expression as:

Vedclass · Accepted Answer

$(a - \sqrt{2}b)(a^{2} + \sqrt{2}ab + 2b^{2})$

Vedclass · Answer

(A) We use the algebraic identity: $a^{3} - b^{3} = (a - b)(a^{2} + ab + b^{2})$.Given expression: $a^{3} - 2\sqrt{2}b^{3}$.Rewrite the expression as: $a^{3} - (\sqrt{2}b)^{3}$.Applying the identity where $x = a$ and $y = \sqrt{2}b$:$= (a - \sqrt{2}b)((a)^{2} + (a)(\sqrt{2}b) + (\sqrt{2}b)^{2})$.$= (a - \sqrt{2}b)(a^{2} + \sqrt{2}ab + 2b^{2})$.

Factorise: $a^{3} - 2\sqrt{2}b^{3}$

Similar Questions

Expand: $(3x + 7y)(3x - 7y)$

Expand $(3x - 1)(3x + 4)$.

Evaluate the following product without multiplying directly: $84 \times 79$

Factorise $: 8 x^{3}+y^{3}-27 z^{3}+18 x y z$

Evaluate $(1002)^{2}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module