(A) We have the expression $x^{2} - \frac{y^{2}}{100}$.This can be rewritten as $x^{2} - (\frac{y}{10})^{2}$.Using the algebraic identity $a^{2} - b^{

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$(x + \frac{y}{10})(x - \frac{y}{10})$

(A) We have the expression $x^{2} - \frac{y^{2}}{100}$.This can be rewritten as $x^{2} - (\frac{y}{10})^{2}$.Using the algebraic identity $a^{2} - b^{2} = (a + b)(a - b)$,where $a = x$ and $b = \frac{y}{10}$,we get:$x^{2} - (\frac{y}{10})^{2} = (x + \frac{y}{10})(x - \frac{y}{10})$.