Factorise x^{2}+9 y^{2}+4+6 x y+12 y+4 x. | vedclass

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Question

(A) We use the algebraic identity: $(a+b+c)^{2} = a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$.Given expression: $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.We can rewrite thi

Vedclass · Accepted Answer

$(x+3y+2)^{2}$

Vedclass · Answer

(A) We use the algebraic identity: $(a+b+c)^{2} = a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$.Given expression: $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.We can rewrite this as:$= (x)^{2} + (3y)^{2} + (2)^{2} + 2(x)(3y) + 2(3y)(2) + 2(2)(x)$.Comparing this with the identity,where $a=x$,$b=3y$,and $c=2$,we get:$= (x+3y+2)^{2}$.Thus,the factors are $(x+3y+2)(x+3y+2)$.

Factorise $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.

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