Factorise 16 x^{2}-40 x y+25 y^{2}. | vedclass

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Question

(B) The given expression is $16 x^{2}-40 x y+25 y^{2}$.We can rewrite this expression as $(4 x)^{2}-2(4 x)(5 y)+(5 y)^{2}$.This is in the form of the

Vedclass · Accepted Answer

$(4 x-5 y)^{2}$

Vedclass · Answer

(B) The given expression is $16 x^{2}-40 x y+25 y^{2}$.We can rewrite this expression as $(4 x)^{2}-2(4 x)(5 y)+(5 y)^{2}$.This is in the form of the algebraic identity $a^{2}-2 a b+b^{2}=(a-b)^{2}$,where $a=4 x$ and $b=5 y$.Substituting these values,we get $(4 x-5 y)^{2}$.

Factorise $16 x^{2}-40 x y+25 y^{2}$.

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