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(B) In all three cases,the materials are arranged in series between the same two temperatures. Since the total thermal resistance $R_{eq} = R_1 + R_2

Vedclass · Accepted Answer

$\Delta T_a = \Delta T_b = \Delta T_c$

Vedclass · Answer

(B) In all three cases,the materials are arranged in series between the same two temperatures. Since the total thermal resistance $R_{eq} = R_1 + R_2 + R_3$ is the same for all three arrangements (as the sum of resistances is independent of the order in series),the total heat current $H = \frac{\Delta T_{total}}{R_{eq}}$ is also the same for all three cases. For any individual material layer,the heat current is given by $H = \frac{\Delta T_{layer}}{R_{layer}}$. Since $H$ is constant and the resistance $R_1$ of material $1$ is constant in all three cases,the temperature difference across material $1$ is $\Delta T_1 = H 	imes R_1$. Therefore,$\Delta T_a = \Delta T_b = \Delta T_c$.

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