Fill in the blanks:
$(i)$ $1 \text{ atm} = \dots \text{ Pascal}$
$(ii)$ $1 \text{ torr} = \dots \text{ Pascal}$
$(iii)$ $1 \text{ bar} = \dots \text{ Pa}$
$(iv)$ $1 \text{ atm} = \dots \text{ cm Hg}$

(N/A) $(i)$ $1 \text{ atm} = 1.01325 \times 10^{5} \text{ Pa}$.
$(ii)$ $1 \text{ torr} = 1 \text{ mm Hg} = \frac{1.01325 \times 10^{5}}{760} \text{ Pa} \approx 133.32 \text{ Pa}$.
$(iii)$ $1 \text{ bar} = 10^{5} \text{ Pa}$.
$(iv)$ $1 \text{ atm} = 76 \text{ cm Hg}$ (since $1 \text{ atm} = 760 \text{ mm Hg} = 76 \text{ cm Hg}$).