Fill in the blank to make the following statement true:
$(729)^{\frac{1}{3}} = \ldots$

  • A
    $17$
  • B
    $13$
  • C
    $9$
  • D
    $1$

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Simplify: $(256)^{4^{-\frac{3}{2}}}$

Find the value of $\frac{4}{(216)^{-\frac{2}{3}}} + \frac{1}{(256)^{-\frac{3}{4}}} + \frac{2}{(243)^{-\frac{1}{5}}}$.

Find the value of $\frac{4}{(216)^{-\frac{2}{3}}} + \frac{1}{(256)^{-\frac{3}{4}}} + \frac{2}{(243)^{-\frac{1}{5}}}$

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$(\frac{3}{5})^4 \times (\frac{3}{5})^{-12} \times (\frac{3}{5})^{6}$

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