Find the value of I_B if V_{BE} = 0.3,V in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the input loop,applying Kirchhoff's Voltage Law $(KVL)$:$6 - (10 	imes 10^3) I_B - V_{BE} - (1 	imes 10^3) I_E = 0$Given $\beta = 100$,we kn

Vedclass · Accepted Answer

$51$

Vedclass · Answer

(A) For the input loop,applying Kirchhoff's Voltage Law $(KVL)$:$6 - (10 	imes 10^3) I_B - V_{BE} - (1 	imes 10^3) I_E = 0$Given $\beta = 100$,we know $I_E = I_B + I_C = I_B + \beta I_B = (1 + \beta) I_B = 101 I_B$.Substituting the values:$6 - 10000 I_B - 0.3 - 1000(101 I_B) = 0$$5.7 - 10000 I_B - 101000 I_B = 0$$5.7 = 111000 I_B$$I_B = \frac{5.7}{111000} \approx 51.35 	imes 10^{-6} A = 51.35\,\mu A$.Rounding to the nearest given option,the value is $51\,\mu A$.

Find the value of $I_B$ if $V_{BE} = 0.3\,V$ in the given circuit $(\beta = 100)$. (in $,\mu A$)

Similar Questions

In an $NPN$ transistor, the collector current is $28 \text{ mA}$. If $80\%$ of the electrons emitted by the emitter reach the collector, what is the base current in $\text{mA}$ (in $\text{ mA}$)?

In a common emitter $(CE)$ amplifier having a voltage gain $G$,the transistor used has a transconductance of $0.03\,mho$ and a current gain of $25$. If the above transistor is replaced with another one with a transconductance of $0.02\,mho$ and a current gain of $20$,the new voltage gain will be:

In an $n-p-n$ transistor,in $CE$ configuration:

In an $N-P-N$ transistor amplifier,the collector current is $9 \ mA$. If $90\%$ of the electrons emitted from the emitter reach the collector,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module