In an $NPN$ transistor, the collector current is $28 \text{ mA}$. If $80\%$ of the electrons emitted by the emitter reach the collector, what is the base current in $\text{mA}$ (in $\text{ mA}$)?

The dc common emitter current gain of an $n-p-n$ transistor is $50$. The potential difference applied across the collector and emitter of a transistor used in $CE$ configuration is $V_{CE} = 2 \ V$. If the collector resistance $R_{C} = 4 \ k\Omega$,the base current $(I_{B})$ and the collector current $(I_{C})$ are:

For a common emitter amplifier,the current gain is $50$. If the emitter current is $6.6 \ mA$,then the value of the current gain when it acts as a common base amplifier is:

For a transistor,$\frac{1}{\alpha_{DC}} - \frac{1}{\beta_{DC}}$ is equal to [where $\alpha_{DC}$ and $\beta_{DC}$ are current amplification factors].

In an $NPN$ transistor,the collector current is $10\, mA$. If $90\%$ of the electrons emitted reach the collector,then:

$A$ transistor works as an amplifier when