Find out the distance between the 2^{nd} and | vedclass

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(A) The radius of the $n^{th}$ orbit of the $H$-atom is given by the formula $r_n = 0.529 	imes n^2 \mathring{A}$.For the $2^{nd}$ orbit $(n=2)$: $r_

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$2.65 \mathring{A}$

Vedclass · Answer

(A) The radius of the $n^{th}$ orbit of the $H$-atom is given by the formula $r_n = 0.529 	imes n^2 \mathring{A}$.For the $2^{nd}$ orbit $(n=2)$: $r_2 = 0.529 	imes (2)^2 = 0.529 	imes 4 = 2.116 \mathring{A}$.For the $3^{rd}$ orbit $(n=3)$: $r_3 = 0.529 	imes (3)^2 = 0.529 	imes 9 = 4.761 \mathring{A}$.The distance between the $2^{nd}$ and $3^{rd}$ orbit is $r_3 - r_2 = 4.761 \mathring{A} - 2.116 \mathring{A} = 2.645 \mathring{A} \approx 2.65 \mathring{A}$.Thus,the correct option is $A$.

Find out the distance between the $2^{nd}$ and $3^{rd}$ orbit of the $H$-atom $:-$

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