Find the HCF of 12,15,and 21. | vedclass

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(A) To find the $HCF$ (Highest Common Factor) of $12$,$15$,and $21$,we first find the prime factorization of each number:$12 = 2^2 	imes 3^1$$15 = 3^

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$3$

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(A) To find the $HCF$ (Highest Common Factor) of $12$,$15$,and $21$,we first find the prime factorization of each number:$12 = 2^2 	imes 3^1$$15 = 3^1 	imes 5^1$$21 = 3^1 	imes 7^1$The $HCF$ is the product of the smallest power of each common prime factor present in the numbers.The only common prime factor is $3$,and its smallest power is $3^1$.Therefore,$HCF$ $(12, 15, 21) = 3$.

Find the $HCF$ of $12$,$15$,and $21$.

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