Find the area of the shaded region given in the figure.

(N/A) The side of the outer square is $14 \, cm$.
The distance from each side of the square to the inner figure is $3 \, cm$.
The inner figure consists of a central square and four semi-circles attached to its sides.
The side length of the inner square is $14 - (3 + 3) = 8 \, cm$.
Since there are four semi-circles attached to the sides of this $8 \, cm$ square,the diameter of each semi-circle is $8 / 2 = 4 \, cm$,so the radius $r = 2 \, cm$.
Area of the outer square $= 14^2 = 196 \, cm^2$.
Area of the inner square $= 8^2 = 64 \, cm^2$.
Area of the four semi-circles $= 4 \times (\frac{1}{2} \pi r^2) = 2 \pi r^2 = 2 \times \pi \times (2)^2 = 8 \pi \, cm^2$.
Area of the unshaded inner region $= \text{Area of inner square} + \text{Area of four semi-circles} = 64 + 8 \pi \, cm^2$.
Area of the shaded region $= \text{Area of outer square} - \text{Area of unshaded inner region} = 196 - (64 + 8 \pi) = 132 - 8 \pi \, cm^2$.