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Question

(C) Given sides of the triangle are $a = 360 \, m$,$b = 450 \, m$,and $c = 450 \, m$.First,calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2}

Vedclass · Accepted Answer

$16200 \sqrt{21} \, m^2$

Vedclass · Answer

(C) Given sides of the triangle are $a = 360 \, m$,$b = 450 \, m$,and $c = 450 \, m$.First,calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2} = \frac{360 + 450 + 450}{2} = \frac{1260}{2} = 630 \, m$.Using Heron's formula,Area = $\sqrt{s(s - a)(s - b)(s - c)}$.Area = $\sqrt{630(630 - 360)(630 - 450)(630 - 450)}$.Area = $\sqrt{630 	imes 270 	imes 180 	imes 180}$.Area = $180 	imes \sqrt{630 	imes 270}$.Area = $180 	imes \sqrt{(90 	imes 7) 	imes (90 	imes 3)}$.Area = $180 	imes 90 	imes \sqrt{7 	imes 3}$.Area = $16200 \sqrt{21} \, m^2$.

Find the area of the triangular field with the length of the sides $360 \, m$,$450 \, m$,and $450 \, m$.

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