Find the circumference and the area of a circular ground with radius $77\, m$.
(N/A) Given,the radius of the circular ground is $r = 77\, m$.
Circumference of a circle is given by the formula $C = 2\pi r$.
Substituting the values,we get $C = 2 \times \frac{22}{7} \times 77 = 2 \times 22 \times 11 = 484\, m$.
Area of a circle is given by the formula $A = \pi r^2$.
Substituting the values,we get $A = \frac{22}{7} \times 77 \times 77 = 22 \times 11 \times 77 = 18634\, m^2$.
Thus,the circumference of the circular ground is $484\, m$ and the area is $18634\, m^2$.
Circumference of a circle is given by the formula $C = 2\pi r$.
Substituting the values,we get $C = 2 \times \frac{22}{7} \times 77 = 2 \times 22 \times 11 = 484\, m$.
Area of a circle is given by the formula $A = \pi r^2$.
Substituting the values,we get $A = \frac{22}{7} \times 77 \times 77 = 22 \times 11 \times 77 = 18634\, m^2$.
Thus,the circumference of the circular ground is $484\, m$ and the area is $18634\, m^2$.
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