Find the distance between the points $P(1, -3, 4)$ and $Q(-4, 1, 2)$.

Show that the points $P(-2, 3, 5)$,$Q(1, 2, 3)$,and $R(7, 0, -1)$ are collinear.

Find the distance between the following pairs of points: $(2, -1, 3)$ and $(-2, 1, 3)$.

The distances of the point $(1, 2, 3)$ from the coordinate axes are:

Name the octant in which each of the following points lies:
$(i) (1, 2, 3)$
$(ii) (4, -2, 3)$
$(iii) (4, -2, -5)$
$(iv) (4, 2, -5)$
$(v) (-4, 2, 5)$
$(vi) (-3, -1, 6)$
$(vii) (2, -4, -7)$
$(viii) (-4, 2, -5)$

If the sum of the squares of the distances of the point $P(x, y, z)$ from the coordinate axes is $242$,then the distance of the point $P$ from the origin is . . . . . . units.