Find the equation of the circle with centre ( | vedclass

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(A) The standard equation of a circle with centre $(h, k)$ and radius $r$ is given by:$(x-h)^{2} + (y-k)^{2} = r^{2}$Given that the centre $(h, k) = (

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$x^{2}+y^{2}-4y=0$

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(A) The standard equation of a circle with centre $(h, k)$ and radius $r$ is given by:$(x-h)^{2} + (y-k)^{2} = r^{2}$Given that the centre $(h, k) = (0, 2)$ and the radius $r = 2$,we substitute these values into the formula:$(x-0)^{2} + (y-2)^{2} = 2^{2}$Expanding the equation:$x^{2} + (y^{2} - 4y + 4) = 4$Simplifying the equation:$x^{2} + y^{2} - 4y + 4 = 4$$x^{2} + y^{2} - 4y = 0$

Find the equation of the circle with centre $(0,2)$ and radius $2$.

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