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(C) The gravitational field $g'$ inside the Earth at a distance $r$ from the center is given by the formula:$g' = \frac{G M r}{R^3}$We know that the a

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$3.06$

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(C) The gravitational field $g'$ inside the Earth at a distance $r$ from the center is given by the formula:$g' = \frac{G M r}{R^3}$We know that the acceleration due to gravity at the surface is $g = \frac{G M}{R^2} \approx 9.8\, m/s^2$.Substituting $g$ into the formula,we get:$g' = g 	imes \frac{r}{R}$Given values:$g = 9.8\, m/s^2$$r = 2000\, km$$R = 6400\, km$Calculating the value:$g' = 9.8 	imes \frac{2000}{6400}$$g' = 9.8 	imes \frac{20}{64}$$g' = 9.8 	imes 0.3125$$g' = 3.0625\, m/s^2$Rounding to two decimal places,we get $3.06\, m/s^2$.

Find the gravitational field at a distance of $2000\, km$ from the center of the Earth. (in $m/s^2$)
(Given: $R_{\text{earth}} = 6400\, km$,$r = 2000\, km$,$M_{\text{earth}} = 6 \times 10^{24}\, kg$)

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Find the gravitational field at a distance of $2000\, km$ from the center of the Earth. (in $m/s^2$)(Given: $R_{\text{earth}} = 6400\, km$,$r = 2000\, km$,$M_{\text{earth}} = 6 \times 10^{24}\, kg$)