Find the highest ratio of IP values of the gi | vedclass

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(C) The Ionization Potential $(IP)$ decreases down a group as the atomic size increases and the valence electrons are further from the nucleus.For nob

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$He : Xe$

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(C) The Ionization Potential $(IP)$ decreases down a group as the atomic size increases and the valence electrons are further from the nucleus.For noble gases,the $IP$ values are: $He (2372 \ kJ/mol)$,$Ne (2080 \ kJ/mol)$,$Ar (1520 \ kJ/mol)$,$Kr (1351 \ kJ/mol)$,$Xe (1170 \ kJ/mol)$.Calculating the ratios:$A) He/Ne = 2372/2080 \approx 1.14$$B) Ne/Ar = 2080/1520 \approx 1.37$$C) He/Xe = 2372/1170 \approx 2.03$$D) Kr/Xe = 1351/1170 \approx 1.15$The highest ratio is obtained for the pair $He : Xe$.

Find the highest ratio of $IP$ values of the given pair of elements.

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