Find the maximum and minimum values of the function given by $h(x) = x + 1, x \in (-1, 1)$.

(NONE) The given function is $h(x) = x + 1$ defined on the open interval $(-1, 1)$.
For any $x \in (-1, 1)$,we have $-1 < x < 1$.
Adding $1$ to all parts of the inequality,we get $-1 + 1 < x + 1 < 1 + 1$,which simplifies to $0 < h(x) < 2$.
As $x$ approaches $-1$ from the right,$h(x)$ approaches $0$,but $h(x)$ is never equal to $0$ because $-1$ is not included in the domain.
As $x$ approaches $1$ from the left,$h(x)$ approaches $2$,but $h(x)$ is never equal to $2$ because $1$ is not included in the domain.
Since the function is strictly increasing and the interval is open,there is no point $c \in (-1, 1)$ such that $h(c)$ is the maximum or minimum value.
Therefore,the function $h(x)$ has neither a maximum nor a minimum value in the interval $(-1, 1)$.