(A) To find the zeros of the polynomial $p(x) = x^{2} - 2x$,we set $p(x) = 0$.$x^{2} - 2x = 0$Factor out $x$ from the expression:$x(x - 2) = 0$This gi

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(A) To find the zeros of the polynomial $p(x) = x^{2} - 2x$,we set $p(x) = 0$.$x^{2} - 2x = 0$Factor out $x$ from the expression:$x(x - 2) = 0$This gives two possible values for $x$:$x = 0$ or $x - 2 = 0$,which implies $x = 2$.Thus,the zeros of the polynomial are $0$ and $2$.Since there are two distinct real values,the number of real zeros is $2$.