Find the order and degree,if defined,of the f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given differential equation is $x y \frac{d^{2} y}{d x^{2}}+x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}=0$.$1$. The order of a differe

Vedclass · Accepted Answer

Order: $2$,Degree: $1$

Vedclass · Answer

(A) The given differential equation is $x y \frac{d^{2} y}{d x^{2}}+x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}=0$.$1$. The order of a differential equation is the order of the highest derivative present in the equation. Here,the highest derivative is $\frac{d^{2} y}{d x^{2}}$,so the order is $2$.$2$. The degree of a differential equation is the power of the highest order derivative,provided the equation is a polynomial in derivatives. Here,the highest order derivative $\frac{d^{2} y}{d x^{2}}$ has an exponent of $1$. Since the equation is a polynomial in terms of its derivatives,the degree is $1$.Therefore,the order is $2$ and the degree is $1$.

Find the order and degree,if defined,of the following differential equation:
$x y \frac{d^{2} y}{d x^{2}}+x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}=0$

Similar Questions

Determine the order and degree (if defined) of the differential equation $y^{\prime} + 5y = 0$.

The degree of the differential equation $\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{2}=\frac{d^{2}y}{dx^{2}}$ is

The order and degree of the differential equation $\left(\frac{d^3 y}{d x^3}\right)^{\frac{1}{2}}-2\left(\frac{d y}{d x}\right)^{\frac{1}{4}}+x y=0$ are respectively

The number of arbitrary constants in the particular solution of a differential equation of fourth order is . . . . . .

The differential equation representing the family of curves ${y^2} = 2c(x + \sqrt{c}),$ where $c$ is a positive parameter,is of

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the order and degree,if defined,of the following differential equation:$x y \frac{d^{2} y}{d x^{2}}+x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}=0$