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(C) The given differential equation is $y^{\prime \prime \prime} + y^2 + e^{y^{\prime}} = 0$.The highest order derivative present in the equation is $

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Order $3$,Degree not defined

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(C) The given differential equation is $y^{\prime \prime \prime} + y^2 + e^{y^{\prime}} = 0$.The highest order derivative present in the equation is $y^{\prime \prime \prime}$,which represents the third derivative.Therefore,the order of the differential equation is $3$.$A$ differential equation is said to have a defined degree if it can be expressed as a polynomial in its derivatives.In this equation,the term $e^{y^{\prime}}$ involves a transcendental function of the derivative $y^{\prime}$,which means the equation cannot be expressed as a polynomial in its derivatives.Thus,the degree of this differential equation is not defined.

Find the order and degree,if defined,of the following differential equation: $y^{\prime \prime \prime} + y^2 + e^{y^{\prime}} = 0$

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