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(B) The reaction is an electrophilic aromatic substitution (nitration) of $N$-phenylbenzamide (benzanilide).The $-NHCOC_6H_5$ group is an ortho/para-d

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$N$-($4$-nitrophenyl)benzamide

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(B) The reaction is an electrophilic aromatic substitution (nitration) of $N$-phenylbenzamide (benzanilide).The $-NHCOC_6H_5$ group is an ortho/para-directing group because the nitrogen atom has a lone pair of electrons that can be delocalized into the benzene ring.Due to the steric hindrance caused by the bulky $-NHCOC_6H_5$ group,the para-position is more accessible than the ortho-position.Therefore,the major product is the para-substituted isomer,which is $N$-($4$-nitrophenyl)benzamide.

Find the major product of the following reaction:
$C_6H_5NHCOC_6H_5 \xrightarrow{conc. HNO_3 + conc. H_2SO_4} \text{Major product}$

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Find the major product of the following reaction:$C_6H_5NHCOC_6H_5 \xrightarrow{conc. HNO_3 + conc. H_2SO_4} \text{Major product}$