Find the roots of the following quadratic equation by factorisation:
$2x^{2} - x + \frac{1}{8} = 0$

  • A
    $x = \frac{1}{4}, \frac{1}{4}$
  • B
    $x = \frac{1}{2}, \frac{1}{2}$
  • C
    $x = \frac{1}{4}, -\frac{1}{4}$
  • D
    $x = \frac{1}{8}, \frac{1}{8}$

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