Find the roots of the quadratic equation usin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given equation is $2x^{2} - 3x - 5 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get:$a = 2, b = -3, c = -5$.The quadrat

Vedclass · Accepted Answer

$\frac{5}{2}, -1$

Vedclass · Answer

(D) The given equation is $2x^{2} - 3x - 5 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get:$a = 2, b = -3, c = -5$.The quadratic formula is given by $x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$.Substituting the values:$x = \frac{-(-3) \pm \sqrt{(-3)^{2} - 4(2)(-5)}}{2(2)}$$x = \frac{3 \pm \sqrt{9 + 40}}{4}$$x = \frac{3 \pm \sqrt{49}}{4}$$x = \frac{3 \pm 7}{4}$.Calculating the two roots:$x_{1} = \frac{3 + 7}{4} = \frac{10}{4} = \frac{5}{2}$$x_{2} = \frac{3 - 7}{4} = \frac{-4}{4} = -1$.Thus,the roots of the equation are $\frac{5}{2}$ and $-1$.

Find the roots of the quadratic equation using the quadratic formula:
$2x^{2} - 3x - 5 = 0$

Similar Questions

Solve the following quadratic equation using the quadratic formula,if the equation has a solution in $R$: $5x^{2} + 8x + 3 = 0$.

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $4 \sqrt{3} x^{2} + 5 x - 2 \sqrt{3} = 0$; $x = \frac{\sqrt{3}}{4}$.

The product of Virat Kohli's age $8$ years ago and $6$ years later is $680$. Find his present age.

Examine whether the following equation is quadratic or not: $(3x + 1)(3x + 2) = (9x - 1)(x + 1)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the roots of the quadratic equation using the quadratic formula:$2x^{2} - 3x - 5 = 0$