The product of Virat Kohli's age 8 years ago | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the present age of Virat Kohli be $x$ years.Age $8$ years ago was $(x - 8)$ years.Age $6$ years later will be $(x + 6)$ years.According to the

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) Let the present age of Virat Kohli be $x$ years.Age $8$ years ago was $(x - 8)$ years.Age $6$ years later will be $(x + 6)$ years.According to the problem,the product of these ages is $680$:$(x - 8)(x + 6) = 680$$x^2 + 6x - 8x - 48 = 680$$x^2 - 2x - 48 - 680 = 0$$x^2 - 2x - 728 = 0$Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$,where $a = 1, b = -2, c = -728$:$x = \frac{2 \pm \sqrt{(-2)^2 - 4(1)(-728)}}{2(1)}$$x = \frac{2 \pm \sqrt{4 + 2912}}{2}$$x = \frac{2 \pm \sqrt{2916}}{2}$$x = \frac{2 \pm 54}{2}$Since age cannot be negative,we take the positive value:$x = \frac{2 + 54}{2} = \frac{56}{2} = 28$Therefore,his present age is $28$ years.

The product of Virat Kohli's age $8$ years ago and $6$ years later is $680$. Find his present age.

Similar Questions

Check whether the following is a quadratic equation:
$(x-3)(2x+1) = x(x+5)$

$x=2$ is a solution of the equation $\ldots \ldots \ldots \ldots.$

$A$ train,travelling at a uniform speed for $360\, km$,would have taken $48\, min$ less to travel the same distance,if its speed were $5\, km/h$ more. Find the original speed of the train (in $km/h$).

Examine whether the following equation is quadratic or not: $x^{2}-3=\frac{2}{x}$

If one of the roots of the equation $kx^{2} + 2x - 3 = 0$ is $2$,then find $k$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module