Find the value of $a$,if the distance between the points $A(-3, -14)$ and $B(a, -5)$ is $9$ units.

The Class $X$ students of a secondary school in Krishinagar have been allotted a rectangular plot of land for their gardening activity. Saplings of Gulmohar are planted on the boundary at a distance of $1\, m$ from each other. There is a triangular grassy lawn in the plot as shown in the Figure. The students are to sow seeds of flowering plants on the remaining area of the plot. Taking $A$ as origin,find the coordinates of the vertices of the triangle.

If the distance between the points $(4, p)$ and $(1, 0)$ is $5,$ then the value of $p$ is

The triangle with the vertices $(1, 1)$, $(-1, -1)$, and $(-\sqrt{3}, \sqrt{3})$ is $\ldots \ldots \ldots$ triangle.

If $A(0, y_{1})$ and $B(0, y_{2})$ are the points on the $Y$-axis,then the distance between them $AB = \ldots$

If $A(0, 0)$,$B(2, 0)$,$C(2, 2)$,and $D(0, 2)$,then $\square ABCD$ is a $\ldots \ldots \ldots$